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trazillion
Before the increasingly popular trazillion, there was bazillion. Bazillion is actually documented in print earlier than simplersounding zillion as an intensification of the number billion by the infix az, in The New York Times in 1939. In 1942 jillion appeared. In 1943 in American Mercury Z. N. Hurston used squillion. In 1944 Damon Runyon used a zillion. In 1978 gazillion was printed.
The indeterminate number, zillion, is formed by the same operation forming the traditional numbers, million, billion, trillion, etc., g(2, 3z + 3, 10).
The number bizillion, analogous to bimillennium, would double the base, so that we get g(2, 3(2z) + 3, 10) = g(2, 6z + 3, 10) for a minimum possible value of 1,000,000,000 = billion. Trizillion = g(2, 3(3z) + 3, 10) = g(2, 9z + 3, 10) > 1,000,000,000,000 = trillion.
André Joyce also defined bazillion as the indeterminate number, g(z, 9, 10), a variation on billion = g(2, 9, 10). Similarly the infix az gives trazillion = g(z, 12, 10), quazadrillion = g(z, 15, 10), quazintillion = g(z, 18, 10), gazoogol = g(z, 50, 100).
Jillion apparently comes from the Engineers' j = g(2, 1/2, 1) = log(1)/pi, so that jillion = g(2, 3g(2, 1/2, 1) + 3, 10) = 3000g(2, g(2, 1/2, 1), 10), an imaginary number.
Squillion, if taken as a contraction of "square zillion", would be g(2, 2, g(2, 3z + 3, 10)) > g(2, 12, 10)
Since, according to Matt Hudelson, at www.sci.wsu.edu/math/faculty/hudelson/moser.html, koogol = kduplex = g(2, k, g(2, 2, 10)) = zoogol and gazoogol = g(z, 50, 100), this gives a new prefix ga and a differentiation between gazillion and kazillion. For gazoogol > zoogol, z > 2 and gazillion = (gazoogol/zoogol)zillion = g(z, 50, 100)/g(2, z, g(2, 2, 10))g(2, 3z + 3, 10) > (g(3, 50, 100)/g(2, 3, g(2, 2, 10))g(2, 12, 10) > gazoogol .
Thus we have, ranking by the second term:
zillion = g(2, 3z + 3, 10) = million, billion, trillion, quadrillion, ...
jillion > zillion
bizillion = g(2, 6z + 3, 10) = billion, quadrillion, sextillion, ...
bazillion = g(z, 9, 10) = ninety, ten billion, totheninethten, ...
trazillion = g(z, 12, 10) = 120, trillion, tothetwelfthten, ...
quazadrilion = g(z, 15, 10) = 150, quadrillion, tothefifteenthten, ...
squillion = g(2, 2, g(2, 3z + 3, 10)) = trillion, quintillion, septillion, ...
zoogol = g(2, z, g(2, 2, 20)) = ten billion, googol, great googol, gargoogol,
gazoogol = g(z, 50, 100) = 50000, googol, tothefiftiethhundred, ...
gazillion > gazoogol
kazillion = g(2, g(2, 3z + 3, 10), 10) = millionplex, billionplex, trillionplex, ....
and by the third term, only bazillion increases in relative rank:
zillion = g(2, 3z + 3, 10) = million, billion, trillion, quadrillion, ...
jillion > zillion
bizillion = g(2, 6z + 3, 10) = billion, quadrillion, sextillion, ...
trazillion = g(z, 12, 10) = 120, trillion, tothetwelfthten, ...
quazadrilion = g(z, 15, 10) = 150, quadrillion, tothefifteenthten, ...
squillion = g(2, 2, g(2, 3z + 3, 10)) = trillion, quintillion, septillion, ...
zoogol = g(2, z, g(2, 2, 20)) = ten billion, googol, great googol, gargoogol,
bazillion = g(z, 9, 10) = ninety, ten billion, totheninethten, ...
gazoogol = g(z, 50, 100) = 50000, googol, tothefiftiethhundred, ...
gazillion > gazoogol
kazillion = g(2, g(2, 3z + 3, 10), 10) = millionplex, billionplex, trillionplex, ..

