trazillion

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trazillion

Before the increasingly popular trazillion, there was bazillion. Bazillion is actually documented in print earlier than simpler-sounding zillion as an intensification of the number billion by the infix -az-, in The New York Times in 1939. In 1942 jillion appeared. In 1943 in American Mercury Z. N. Hurston used squillion. In 1944 Damon Runyon used a zillion. In 1978 gazillion was printed.

The indeterminate number, zillion, is formed by the same operation forming the traditional numbers, million, billion, trillion, etc., g(2, 3z + 3, 10).

The number bizillion, analogous to bimillennium, would double the base, so that we get g(2, 3(2z) + 3, 10) = g(2, 6z + 3, 10) for a minimum possible value of 1,000,000,000 = billion. Trizillion = g(2, 3(3z) + 3, 10) = g(2, 9z + 3, 10) > 1,000,000,000,000 = trillion.

André Joyce also defined bazillion as the indeterminate number, g(z, 9, 10), a variation on billion = g(2, 9, 10). Similarly the infix -az- gives trazillion = g(z, 12, 10), quazadrillion = g(z, 15, 10), quazintillion = g(z, 18, 10), gazoogol = g(z, 50, 100).

Jillion apparently comes from the Engineers' j = g(2, 1/2, -1) = log(-1)/pi, so that jillion = g(2, 3g(2, 1/2, -1) + 3, 10) = 3000g(2, g(2, 1/2, -1), 10), an imaginary number.

Squillion, if taken as a contraction of "square zillion", would be g(2, 2, g(2, 3z + 3, 10)) > g(2, 12, 10)

Since, according to Matt Hudelson, at www.sci.wsu.edu/math/faculty/hudelson/moser.html, k-oogol = k-duplex = g(2, k, g(2, 2, 10)) = zoogol and gazoogol = g(z, 50, 100), this gives a new prefix ga- and a differentiation between gazillion and kazillion. For gazoogol > zoogol, z > 2 and gazillion = (gazoogol/zoogol)zillion = g(z, 50, 100)/g(2, z, g(2, 2, 10))g(2, 3z + 3, 10) > (g(3, 50, 100)/g(2, 3, g(2, 2, 10))g(2, 12, 10) > gazoogol .

Thus we have, ranking by the second term:

zillion = g(2, 3z + 3, 10) = million, billion, trillion, quadrillion, ...

jillion > zillion

bizillion = g(2, 6z + 3, 10) = billion, quadrillion, sextillion, ...

bazillion = g(z, 9, 10) = ninety, ten billion, to-the-nineth-ten, ...

trazillion = g(z, 12, 10) = 120, trillion, to-the-twelfth-ten, ...

quazadrilion = g(z, 15, 10) = 150, quadrillion, to-the-fifteenth-ten, ...

squillion = g(2, 2, g(2, 3z + 3, 10)) = trillion, quintillion, septillion, ...

zoogol = g(2, z, g(2, 2, 20)) = ten billion, googol, great googol, gargoogol,

gazoogol = g(z, 50, 100) = 50000, googol, to-the-fiftieth-hundred, ...

gazillion > gazoogol

kazillion = g(2, g(2, 3z + 3, 10), 10) = millionplex, billionplex, trillionplex, ....

and by the third term, only bazillion increases in relative rank: